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Floor((5^n-1)/n).
1

%I #19 Sep 08 2022 08:46:05

%S 4,12,41,156,624,2604,11160,48828,217013,976562,4438920,20345052,

%T 93900240,435965401,2034505208,9536743164,44878791360,211927625868,

%U 1003867701480,4768371582031,22706531343005,108372081409801,518301258916440,2483526865641276

%N Floor((5^n-1)/n).

%H Vincenzo Librandi, <a href="/A225586/b225586.txt">Table of n, a(n) for n = 1..300</a>

%t Table[Floor[(5^n - 1) / n], {n, 30}] (* or *) Table[Quotient[5^n - 1, n], {n, 30}]

%o (Magma) [Floor((5^n-1)/n): n in [1..30]];

%Y Cf. A024049, A034474, A082482, A129795.

%K nonn,easy

%O 1,1

%A _Vincenzo Librandi_, May 30 2013