OFFSET
1,1
COMMENTS
Row 5 of A211849.
LINKS
R. H. Hardin, Table of n, a(n) for n = 1..210
FORMULA
Empirical: a(n) = (43/24)*n^4 + (185/12)*n^3 + (1217/24)*n^2 + (937/12)*n + 50.
Conjectures from Colin Barker, Jul 20 2018: (Start)
G.f.: x*(196 - 419*x + 457*x^2 - 241*x^3 + 50*x^4) / (1 - x)^5.
a(n) = 5*a(n-1) - 10*a(n-2) + 10*a(n-3) - 5*a(n-4) + a(n-5) for n>5.
(End)
EXAMPLE
Some solutions for n=3:
..0....0....0....0....0....0....0....0....0....0....0....0....0....0....0....0
..0....1....1....1....0....1....0....1....1....1....1....1....1....0....1....1
..1....1....1....1....1....0....1....0....1....1....1....1....1....0....1....1
..1....1....2....1....1....0....1....0....2....2....2....2....2....1....2....1
..2....2....2....2....2....2....1....2....2....2....1....2....1....1....2....2
..2....1....2....1....1....2....2....2....2....3....1....2....1....2....3....1
..3....1....3....1....1....3....2....2....3....2....1....3....3....2....2....1
..3....3....3....1....1....3....0....3....3....2....1....3....3....3....2....3
..0....3....3....3....3....3....0....3....3....4....3....4....4....3....3....3
..0....4....4....3....3....3....3....2....4....2....3....3....3....4....2....4
..4....4....3....4....4....4....3....2....4....4....3....3....4....3....2....4
..0....5....3....3....3....4....4....4....3....2....4....0....4....4....4....2
CROSSREFS
KEYWORD
nonn
AUTHOR
R. H. Hardin, Apr 22 2012
STATUS
approved