login
A190651
Years with exactly one "Friday the 13th", starting from 1901.
4
1902, 1904, 1909, 1910, 1913, 1915, 1916, 1919, 1921, 1924, 1926, 1927, 1930, 1932, 1937, 1938, 1941, 1943, 1944, 1947, 1949, 1952, 1954, 1955, 1958, 1960, 1965, 1966, 1969, 1971, 1972, 1975, 1977, 1980, 1982, 1983, 1986, 1988, 1993, 1994, 1997, 1999, 2000
OFFSET
1,1
LINKS
FORMULA
A101312(a(n)) = 1, 1 <= A101312(n) <= 3.
EXAMPLE
1902 is a term, since only Jun 13 1902 fell on a Friday.
MATHEMATICA
Select[Range[1901, 2001], Count[Table[DayName@{#, m, 13}, {m, 12}], Friday]==1&] (* Giorgos Kalogeropoulos, Sep 12 2021 *)
PROG
(Haskell)
a190651 n = a190651_list !! (n-1)
a190651_list = filter ((== 1) . a101312) [1901..]
(Python)
from datetime import date
def ok(n): return sum(date.isoweekday(date(n, m, 13)) == 5 for m in range(1, 13)) == 1
print(list(filter(ok, range(1901, 2001)))) # Michael S. Branicky, Sep 12 2021
CROSSREFS
KEYWORD
nonn
AUTHOR
Reinhard Zumkeller, May 16 2011
STATUS
approved