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Positions of 0 in A190224; complement of A190226.
3

%I #12 Dec 28 2017 03:41:35

%S 2,4,5,6,7,8,10,12,13,14,16,18,19,20,21,22,24,26,27,28,29,30,32,34,35,

%T 36,37,38,40,42,43,44,46,48,49,50,51,52,54,56,57,58,59,60,62,64,65,66,

%U 67,68,70,71,72,73,74,76,78,79,80,81,82,84,86,87,88,89,90,92,94,95,96,97,98,100,101,102,103,104,106,108,109,110,111,112,114

%N Positions of 0 in A190224; complement of A190226.

%H G. C. Greubel, <a href="/A190225/b190225.txt">Table of n, a(n) for n = 1..8000</a>

%t u = Sin[Pi/3]; v = Cos[Pi/3];

%t f[n_] := Floor[n*u + n*v] - Floor[n*u] - Floor[n*v]

%t t = Table[f[n], {n, 1, 120}] (* A190224 *)

%t Flatten[Position[t, 0]] (* A190225 *)

%t Flatten[Position[t, 1]] (* A190226 *)

%o (PARI) is(n) = my(u = sin(Pi/3), v = cos(Pi/3)); !(floor(n*u + n*v) - floor(n*u) - floor(n*v)) \\ _Iain Fox_, Dec 27 2017

%Y Cf. A190224, A190226.

%K nonn

%O 1,1

%A _Clark Kimberling_, May 06 2011