%I #4 Mar 30 2012 18:57:24

%S 1,1,0,1,0,1,0,1,1,0,0,0,1,1,1,1,0,0,0,0,0,1,1,1,1,1,1,0,0,0,0,1,0,0,

%T 0,1,1,1,1,0,1,0,1,0,1,1,0,0,0,0,0,1,1,0,1,1,0,1,0,1,0,1,1,1,1,1,1,0,

%U 0,0,1,0,0,0,1,0,0,1,0,0,1,0,0,0,0,0,0,1,0,1,1,1,1,0,1,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,1,0,1,1,1,0,0,1,0,0,0,0,0,0,1,0,0,1,0,0,1,0,0,0,0,0,1

%N Zero-one sequence based on the sequence (4n): a(A008586(k))=a(k); a(A042968(k))=1-a(k), a(1)=0, a(2)=0, a(3)=1.

%t u[n_] := 4n; (*A008586*)

%t a[1] = 0; a[2]=0; a[3]=1; h = 128;

%t c = (u[#1] &) /@ Range[2h];

%t d = (Complement[Range[Max[#1]], #1] &)[c]; (*A042968*)

%t Table[a[d[[n]]] = 1 - a[n], {n, 1, h - 1}]; (*A189292*)

%t Table[a[c[[n]]] = a[n], {n, 1, h}] (*A189292*)

%t Flatten[Position[%, 0]] (*A189293*)

%t Flatten[Position[%%, 1]] (*A189294*)

%Y Cf. A188967, A189293, A189294, A189289, A189295, A189298.

%K nonn

%O 1

%A _Clark Kimberling_, Apr 19 2011