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a(n) = 11^(2^n).
0

%I #13 Sep 08 2022 08:45:52

%S 11,121,14641,214358881,45949729863572161,

%T 2111377674535255285545615254209921,

%U 4457915684525902395869512133369841539490161434991526715513934826241

%N a(n) = 11^(2^n).

%F a(n+1) = a(n)^2 with a(0)=11.

%F a(n) = A001020(A000079(n)). - _Michel Marcus_, Sep 13 2015

%t Table[11^2^n, {n, 0, 6}] (* _Vincenzo Librandi_, Sep 13 2015 *)

%o (Magma) [11^2^n: n in [0..6]]; // _Vincenzo Librandi_, Sep 13 2015

%o (PARI) a(n)=11^(2^n) \\ _Charles R Greathouse IV_, Apr 15 2020

%Y Cf. A000079, A001020.

%K nonn,easy

%O 0,1

%A _Vincenzo Librandi_, Apr 21 2010

%E Offset corrected by _R. J. Mathar_, Jun 18 2010