%I #6 Apr 09 2014 10:15:20

%S 2,4,6,9,12,15,18,21,25,30,35,39,42,45,50,56,60,64,69,72,76,81,85,91,

%T 99,102,105,108,111,120,129,135,138,144,150,155,160,165,170,176,180,

%U 186,192,195,198,207,217,225,228,231,236,240,246,255,260,265,270,275,279

%N a(n) = the single multiple of A143117(n) such that n-th prime <= a(n) <= (n+1)th prime.

%e The 16th prime is 53 and the 17th prime is 59. So we will concern ourselves with the integers 53,54,55,56,57,58,59. 1 divides all these integers. 2 divides three of these integers (54,56,58). 3 divides 54 and 57. 4 divides just 56. So a(16) = 56.

%Y Cf. A143117.

%K nonn

%O 1,1

%A _Leroy Quet_, Jul 25 2008

%E Extended by _Ray Chandler_, Nov 10 2008