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a(n) = 2 + floor((1 + Sum_{j=1..n-1} a(j))/3).
2

%I #9 Jun 05 2023 08:52:53

%S 2,3,4,5,7,9,12,16,21,28,38,50,67,89,119,159,212,282,376,502,669,892,

%T 1189,1586,2114,2819,3759,5012,6682,8910,11880,15840,21120,28160,

%U 37546,50062,66749,88999,118665,158220,210960,281280,375040,500053,666738

%N a(n) = 2 + floor((1 + Sum_{j=1..n-1} a(j))/3).

%H G. C. Greubel, <a href="/A120149/b120149.txt">Table of n, a(n) for n = 1..1000</a>

%t f[s_] := Append[s, Floor[(7 + Plus @@ s)/3]]; Nest[f, {2}, 44] (* _Robert G. Wilson v_, Jul 08 2006 *)

%o (SageMath)

%o @CachedFunction

%o def A120149(n): return 2 + (1+sum(A120149(k) for k in range(1,n)))//3

%o [A120149(n) for n in range(1, 61)] # _G. C. Greubel_, Jun 04 2023

%Y Cf. A072493, A073941, A112088.

%K nonn

%O 1,1

%A _Graeme McRae_, Jun 10 2006

%E More terms from _Robert G. Wilson v_, Jul 08 2006