OFFSET
1,1
COMMENTS
Conjecture: There will always be an x,y,n such that x^2 + p = y^n for all primes p. In otherwords, there is a one-one mapping of the prime numbers to y^n - x^2 for some x,y,n. Therefore primes of the form y^n - x^2 are infinite in number.
EXAMPLE
5 is the smallest number that when we add its square to prime 2, we get a
perfect power, 3^3. 1 is the smallest number that when we add its square to
prime 3, we get a perfect power, 2^2. So 5 and 1 are the first two entries in
the table.
PROG
(PARI) sqplusp(n) = { local(p, x, y, c=0); forprime(p=2, n, for(x=1, n, y=x^2+p; if(ispower(y), print1(x", "); c++; break ) ) ); print(); print(c) }
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Cino Hilliard, Feb 26 2006
STATUS
approved