OFFSET
0,5
COMMENTS
Subdiagonal S(n+1,n) is A000975(n+1). Row sums of inverse are 0^n.
FORMULA
Number triangle T(n, k)=T(n-1, k-1)+J(k+1)*T(n-1, k) where J(n)=A001045(n); Column k has g.f. x^k/Product(1-J(i+1)x, i, 0, k).
EXAMPLE
Triangle begins
1....1....3....5...11...21...43....J(k+1)
1
1....1
1....2....1
1....3....5....1
1....4...18...10....1
1....5...58...68...21....1
1....6..179..398..299...42....1
For example, T(6,3)=398=58+5*68=T(5,2)+J(4)*T(5,3).
CROSSREFS
KEYWORD
AUTHOR
Paul Barry, Nov 14 2005
STATUS
approved