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A113191
Difference of two Lucas numbers.
4
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 14, 15, 16, 17, 18, 22, 25, 26, 27, 28, 29, 36, 40, 43, 44, 45, 46, 47, 58, 65, 69, 72, 73, 74, 75, 76, 94, 105, 112, 116, 119, 120, 121, 122, 123, 152, 170, 181, 188, 192, 195, 196, 197, 198, 199, 246, 275, 293, 304
OFFSET
1,3
COMMENTS
Also the sum of consecutive Lucas numbers because the difference L(i) - L(j) equals the sum L(j+1) + ... + L(i+2).
Conjecture: L(m) - L(n) with m > 1 and m > n >= 0 is a perfect power but not a square only for (m,n) = (7,0), (5,2). This has been verified for n < m <= 500. Note that L(7) - L(0) = 29 - 2 = 3^3 and L(5) - L(2) = 11 - 3 = 2^3. - Zhi-Wei Sun, Jan 02 2025
MATHEMATICA
Lucas[n_] := Fibonacci[n+1]+Fibonacci[n-1]; Union[Flatten[Table[Lucas[n]-Lucas[i], {n, 13}, {i, 0, n-2}]]]
CROSSREFS
Cf. A000032 (Lucas numbers), A007298 (difference of two Fibonacci numbers).
Cf. A221471, A221472 (square root of squares in this sequence).
Sequence in context: A130574 A023780 A035064 * A191923 A191922 A230776
KEYWORD
nonn
AUTHOR
T. D. Noe, Oct 17 2005
STATUS
approved