%I #3 Dec 15 2017 17:36:56

%S 1,1,1,1,1,1,1,1,1,1,3,1,2,3,3,4,3,1,3,1,1,2,3,1,5,3,1,5,3,1,2,6,3,5,

%T 3,1,3,3,3,1,3,1,3,3,1,4,3,1,3,1,3,5,3,1,2,3,4,2,3,1,5,5,1,3,3,2,2,3,

%U 3,1,3,1,3,3,3,2,3,5,3,1,1,5,3,1,2,3,3,5,3,1,4,9,4,3,3,9,2,5,3,1,3,1,2,2,6

%N Number of consecutive integers starting with n needed to sum to a Niven number.

%e a(25)=5 because 25 + 26 + 27 + 28 + 29 = 135 and 135/9 = 15, 5 consecutive

%e integers are needed.

%Y Cf. A005349, A110029, A110031.

%K base,easy,nonn

%O 1,11

%A _Jason Earls_, Jul 08 2005