OFFSET
1,1
COMMENTS
A104758: the number of cubes m = k^3 such that n <= m <= (n+1)^2.
MATHEMATICA
f[n_] := Floor[(n + 1)^(2/3)] - Floor[n^(1/3)] + If[ IntegerQ[n^(1/3)], 1, 0]; t = Table[ f[n], {n, 0, 867}]; Count[t, # ] & /@ Range[81]
CROSSREFS
KEYWORD
nonn
AUTHOR
Giovanni Teofilatto and Robert G. Wilson v, May 10 2005
STATUS
approved