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Numbers n such that the number formed by the digits of 2n sorted in ascending order is equal to the sum of the divisors of n after the digits of each divisor have been sorted in ascending order.
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%I #8 Dec 15 2017 17:36:19

%S 6,28,487,4204,17208,20044,20404,25741,34687,36847,41257,42004,42571,

%T 48673,51427,97398,125407,140439,140527,200404,204004,207541,250741,

%U 254071,257401,304687,304867,368047,402004,407521,410257,425071,425107

%N Numbers n such that the number formed by the digits of 2n sorted in ascending order is equal to the sum of the divisors of n after the digits of each divisor have been sorted in ascending order.

%C Primes with certain digits and various combinations of those digits along with any number of zeros inserted are members. E.g., primes of the form 425(0_z)71, or 71+17*2^n*5^(n+2) for n>1 and primes of the form 25(0_z)741 or 741+2^n*5^(n+2) for n>2 etc. are in this sequence.

%e a(4)=4204 because the digits of 2*4204 sorted ascending are 488; the divisors of 4204 are [1, 2, 4, 1051, 2102, 4204] and 1+2+4+115+122+244 = 488.

%K base,nonn

%O 1,1

%A _Jason Earls_, Jun 11 2003