OFFSET
1,1
COMMENTS
For all but three of the terms through a(41)=274, the reciprocal of the largest prime factor of 10^a(n)-1 is a decimal fraction with a period of a(n)/2. Of the three exceptions, there are two (a(32)=231 and a(38)=264) where the period is a(n)/3, and one (a(19)=132) where the period is a(n)/4. - Jon E. Schoenfield, Jun 27 2010
LINKS
Makoto Kamada, Factorizations of 11...11 (repunit).
EXAMPLE
30 is in the sequence because the factorization of 10^30-1 is 3^3*7*11*13*31*37*41*211*241*271*2161*9091*2906161 and 2906161 occurs already in 10^15-1=3^3*31*37*41*271*2906161 producing a decimal fraction with a period of 15, (1/2906161=0.000000344096559000000344096559000000344...)
CROSSREFS
KEYWORD
more,nonn
AUTHOR
Hugo Pfoertner, Mar 18 2003
EXTENSIONS
More terms from Hans Havermann, May 31 2003
Terms a(31)-a(37) from Jon E. Schoenfield, Jun 19 2010
Terms a(38)-a(41) added, link added, and earlier comment expanded by Jon E. Schoenfield, Jun 27 2010
a(42)-a(54) from Max Alekseyev, Aug 17 2013, Apr 26 2022
STATUS
approved