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A054874
a(n) = 2^(sum of a(i) where i<n).
1
0, 1, 2, 8, 2048
OFFSET
0,3
COMMENTS
The next term is too large to include.
FORMULA
a(n) = 2^A034797(n-1) = A034797(n) - A034797(n-1)
EXAMPLE
a(4) = 2^(0+1+2+8) = 2^11 = 2048; a(5) = 2^2059>10^619
CROSSREFS
Cf. A014221, A034797 for partial sum, so a(n) is number of impartial games with value n-1, using natural enumeration of impartial games.
Sequence in context: A306241 A073630 A027733 * A174736 A324567 A135238
KEYWORD
easy,nonn
AUTHOR
Henry Bottomley, May 26 2000
STATUS
approved