OFFSET
1,4
COMMENTS
Comment from Jinyuan Wang, Oct 19 2019 (Start)
This is also the number of nonempty subsets of {1,2,...,n} in which exactly 1/3 of the elements are <= (n+1)/3.
Proof: Let b(n) = number of nonempty subsets of {1,2,...,n} in which exactly 1/3 of the elements are <= (n+1)/3.
We only need to prove b(3k-1) = a(3k-1).
Now a(3k-1) = Sum_{m=1..k-1} binomial(k-1, m)*binomial(2k, 2m).
b(3k-1) = Sum_{m=1..k-1} binomial(k, m)*binomial(2k-1, 2m).
Because binomial(k-1, m)*binomial(2k, 2m) = binomial(k, m)*binomial(2k-1, 2m), we have b(3k-1) = a(3k-1). (End)
CROSSREFS
KEYWORD
nonn
AUTHOR
STATUS
approved