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Continued fraction for sqrt(809).
1

%I #11 Jun 22 2022 16:20:27

%S 28,2,3,1,7,2,1,6,2,3,11,11,3,2,6,1,2,7,1,3,2,56,2,3,1,7,2,1,6,2,3,11,

%T 11,3,2,6,1,2,7,1,3,2,56,2,3,1,7,2,1,6,2,3,11,11,3,2,6,1,2,7,1,3,2,56,

%U 2,3,1,7,2,1,6,2,3,11,11,3,2,6,1,2,7,1,3,2,56,2,3

%N Continued fraction for sqrt(809).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_21">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(809)),confrac);

%t ContinuedFraction[Sqrt[809],120] (* or *) PadRight[{28},120,{56,2,3,1,7,2,1,6,2,3,11,11,3,2,6,1,2,7,1,3,2}] (* _Harvey P. Dale_, Jun 22 2022 *)

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_.