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a(n) = (10*n + 9)^5.
1

%I #12 Sep 08 2022 08:44:42

%S 59049,2476099,20511149,90224199,282475249,714924299,1564031349,

%T 3077056399,5584059449,9509900499,15386239549,23863536599,35723051649,

%U 51888844699,73439775749,101621504799,137858491849

%N a(n) = (10*n + 9)^5.

%H Vincenzo Librandi, <a href="/A017381/b017381.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_06">Index entries for linear recurrences with constant coefficients</a>, signature (6, -15, 20, -15, 6, -1).

%o (Magma) [(10*n+9)^5: n in [0..20]]; // _Vincenzo Librandi_, Sep 01 2011

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_