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53.MaximumSubarray.js
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93 lines (84 loc) · 2.08 KB
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/*
* @Author: SkylineBin
* @Date: 2019-06-23 15:34:16
* @Last Modified by: SkylineBin
* @Last Modified time: 2019-06-23 16:58:20
*/
/****
*
* 求一个数组的顺序和最大的子数组
*
*
*/
/**
* @param {number[]} nums
* @return {number}
*/
var maxSubArray = function(nums) {
let maxSum = -1*Number.MAX_VALUE;
if(nums.length === 1){
return nums[0];
}
for (let i = 0; i < nums.length; i++) {
for (let j = i+1; j <=nums.length; j++) {
let sum = nums[i];
for (let m = i+1; m <j; m++) {
sum += nums[m];
}
if(sum > maxSum){
maxSum = sum;
}
}
}
return maxSum;
};
// 以上方案超时
let nums = [-2,1,-3,4,-1,2,1,-5,4];
// console.log(maxSubArray(nums));
var maxSubArray2 = function(nums) {
let maxSum = -1*Number.MAX_VALUE;
if(nums.length === 1){
return nums[0];
}
for (let i = 0; i < nums.length; i++) {
let sum = nums[i];
for (let j = i+1; j < nums.length; j++) {
sum += nums[j];
maxSum = Math.max(maxSum,sum,nums[i],nums[j]);
}
}
return maxSum;
};
console.log(maxSubArray2(nums));
var maxSubArray3 = function(nums) {
let maxSum = -1*Number.MAX_VALUE;
if(nums.length === 1){
return nums[0];
}
for (let i = 0; i < nums.length; i++) {
let sum = nums[i];
for (let j = i+1; j < nums.length; j++) {
sum += nums[j];
if(maxSum < sum){
maxSum = dum;
}
if(maxSum < nums[i]){
maxSum = nums[i];
}
if(maxSum < nums[j]){
maxSum = nums[j];
}
}
}
return maxSum;
};
// 以下方案是时间复杂度最低,空间复杂度较高
var maxSubArray4 = function(nums) {
let globalMax = nums[0],
localMax = nums[0];
for (let i = 1; i < nums.length; i++) {
localMax = Math.max(nums[i], nums[i] + localMax);
globalMax = Math.max(globalMax, localMax);
}
return globalMax;
};